The gradient of this graph is equal to the capacitance of the capacitor. \(C= \frac{Q}{V}\) And the area under the graph is the energy stored by the capacitor.
If a larger value of resistance were used with the same value of capacitance in the above circuit, then a smaller current would flow, therefore it would take longer for the capacitor to charge up and ...
CBSE Class 12 Current Electricity Notes PDF: Have a look at the chapter notes from CBSE 12th Physics Chapter 3 Current Electricity. These notes have been prepared by subject matter experts for 2023-24 ...
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