The default network mask dictates the total number of bits available for all network numbers in that range. Therefore in 'class B' first 16 bits are used for numbering the networks, as the …

Also, Class B addresses of 172.16.0.0 to 172.31.255.255 have been allocated for the same purposes, so they can be summarized as 172.16.0.0/12. As Juergen rightly pointed out, …

if we take /23 notation for 172.16.0.0 class B network,we will get 128 network and 510 hosts.Here we are borrowing 7 bit for network and 9 bit for host (2^7=128 and 2^9=512)

The Cisco Learning Network has developed an IPv4 subnet chart to help aid in your learning. This chart organizes Class A, B, and C networks and various subnets.

The class B address in the table, you are dealing with a range of private classfull class B address. The Class B address structure defines 16 bits for the network parts. Including the 172.16.0.0, …

The number of network, subnet, and host bits must total 32 bits, making one of the answers incorrect. The answer with 8 network bits cannot be correct because the question states that a …

For example, while 10.0.0.0/8 was a single class A network, it is common for organizations to divide it into smaller /16 or /24 networks. Contrary to a common misconception, a /16 subnet of …

So they simply listed the range in which base addresses of class B networks can be found, and that range ends with 191.255.0.0 (because all higher ip addresses in the range 128.0.0.0 - …

A long time ago before subnet masks, this is how a device decided which Class an address belonged to and thereby determined which bits were interpreted as network bits and which bits …

Address 127.0.0.0 looks like a Class A network ID, but it begins with a reserved value (127), so it is not in any Class A, B, or C network. 172.20.0.1 is a Class B address, with the last two octets …