
pumping lemma: ww^R not regular - Mathematics Stack Exchange
I'm trying to prove that $L = \ {ww^R : w \in \ {a,b\}^*\}$ ($w^R$ is the reverse of $w$) is not regular using the pumping lemma. Let $p$ be the pumping length and $s ...
Context free grammar: Meaning of notation ww^R
Aug 22, 2017 · A common example in CFG is the palindrome example. These examples often contain the $\\ ww^R$ notation for the string. An example from my class could be: Strings $\\ ww^R$ over the …
how to determine if a context free language is deterministic or ...
Jun 9, 2018 · how to determine if a context free language is deterministic or nondeterministic in general to make sure a language is deterministic we can make DPDA for it how can we make sure of …
Prove that $\ {ww^R\#ww^R\}$ is not context free
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Construct PDA that accepts the language $L = \ {w_1cw_2 : w_1, w_2 \in ...
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formal languages - Pumping lemma, L= {WW^R | W can be {1 ...
Feb 5, 2019 · im trying to find out, if L is regular or not using pumping lemma. I have L={WW^R | W can be {1}+} So possible strings would be 11, 1111, 111111. In every cases i have googled so far are …
Is it possible to make a PDA for $\ { ww : w \in \ { 0,1 \}^* \}$?
Consider the language $L = \ { ww : w \in \ { 1,0 \}^* \}$. I know it's easy to make a PDA for $\ { w w^\text {R} : w \in \ { 0,1 \}^* \}$ where $w^ {\text {R}}$ is ...
computer science - Proving that $\ {ww^rx | w,x \in \ {a,b ...
Apr 14, 2016 · I've tried several strings, like apbbap a p b b a p that work with the palindrome language (wwr w w r), but the last x∈ {a,b}+ x ∈ {a, b} + makes it harder to prove, because it can actually be …
Find a grammar that generates this palindrome language
This is a homework problem. The problem is: Find a grammar that generates this language: L = {wcw^R: w ∈ {a,b}+ } over alphabet Σ = {a, b, c}. I have tried many different transitions, but can't...
Proving the language $\ {w \in \ {0, 1\}^ {\ast} : w = w^ {R}$, $|w ...
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